Abstract
We investigate complete minimal hypersurfaces in the Euclidean space ${R}^{4}$, with Gauss-Kronecker curvature identically zero. We prove that, if $f:M^{3}\rightarrow {R}^{4}$ is a complete minimal hypersurface with Gauss-Kronecker curvature identically zero, nowhere vanishing second fundamental form and scalar curvature bounded from below, then $f(M^{3})$ splits as a Euclidean product $L^{2}\times {R}$, where $L^{2}$ is a complete minimal surface in $ {R}^{3}$ with Gaussian curvature bounded from below.
Citation
T. Hasanis. A. Savas-Halilaj. T. Vlachos. "Minimal hypersurfaces with zero Gauss-Kronecker curvature." Illinois J. Math. 49 (2) 523 - 529, Summer 2005. https://doi.org/10.1215/ijm/1258138032
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